Ponder This Challenge - February 2026 - Blot-avoiding backgammon strategy
- Ponder This
Ponder This Challenge:
Design 25 cubes so that each cube's six faces display integer numbers in the range 0,1,...,31 such that:
Please give your answer as 25 lines of six numbers.
Bonus question: Use as small a range of numbers as possible.
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Using 31 different numbers, we can get 31 cubes by using the projective plane of order 5 (see http://mathworld.wolfram.com/ProjectivePlane.html) that has 31 points and 31 lines. Each line contains exactly six points, and any two distinct lines have exactly one point in common: 0 1 2 3 4 5
0 6 7 8 9 10
0 11 12 13 14 15
0 16 17 18 19 20
0 21 22 23 24 25
1 6 11 16 21 26
1 7 12 18 23 28
1 9 15 17 25 29
1 10 14 20 24 27
2 6 13 18 24 29
2 7 11 17 22 27
2 8 14 16 25 28
2 10 15 19 23 26
3 6 12 19 25 27
3 8 11 20 23 29
3 9 14 18 22 26
3 10 13 17 21 28
4 7 13 20 25 26
4 8 15 18 21 27
4 9 11 19 24 28
4 10 12 16 22 29
5 6 15 20 22 28
5 7 14 19 21 29
5 8 12 17 24 26
5 9 13 16 23 27
0 26 27 28 29 30
1 8 13 19 22 30
2 9 12 20 21 30
3 7 15 16 24 30
4 6 14 17 23 30
5 10 11 18 25 30
If we throw away the last six lines that pass through the last point, we get 25 lines (cubes) using 30 points (numbers). To prove that this is the best solution attainable note that if a solution existed that used less than 30 different numbers, then by the pigeonhole principle at least one of the numbers must be used six times (150/29) and these six cubes would have 31 different numbers.