Ponder This Challenge - February 2026 - Blot-avoiding backgammon strategy
- Ponder This
Ponder This Challenge:
There are seven polyhedral dice in a Dungeons & Dragons game. The result of throwing the 7 D&D dice is the sum of the seven numbers from each die:
Find a way to get the same distribution (same probability for each result) of tossing all seven D&D cubes by tossing four Disdyakis Triacontahedrons with integer numbers between 1 and 17 on their 120 faces.
Please supply your answer as four lines of 17 numbers. Line i describes the i-th Disdyakis Triacontahedron and Column j describes how many times the number j appears on it.
We will post the names of those who submit a correct, original solution! If you don't want your name posted then please include such a statement in your submission!
We invite visitors to our website to submit an elegant solution. Send your submission to the ponder@il.ibm.com.
If you have any problems you think we might enjoy, please send them in. All replies should be sent to: ponder@il.ibm.com
The cubes can be seen as polynomials, where tossing a cube gives n with a probability proportional to the coefficient of the monomial x^n.
Using this notation, it is easy to see that summing several cubes is the same as multiplying their polynomials.
So all we have to do is take the seven polynomials:
x+x^2+x^3+x^4
x+x^2+x^3+x^4+x^5+x^6
x+x^2+x^3+x^4+x^5+x^6+x^7+x^8
1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+X^9
1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+X^9
x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+X^9+X^10+x^11+X^12
x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+X^9+X^10+x^11+X^12+...+X^20
Factor them and then multiply the factors together in a different way.
There are many different ways to do this.
A possible solution, in the format we asked for, is
0 5 5 5 5 10 10 10 10 10 10 10 10 5 5 5 5
3 3 6 6 6 9 9 12 12 12 9 9 6 6 6 3 3
3 9 12 12 12 9 3 0 0 0 3 9 12 12 12 9 3
1 2 4 6 8 10 11 12 12 12 11 10 8 6 4 2 1